Question
Answer
$$\dfrac{\sqrt{41}}{\sqrt{41}}=1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{41}}{\sqrt{41}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{\sqrt{41}}{\sqrt{41}}\frac{\sqrt{41}}{\sqrt{41}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{41}{41} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}} \frac{ 41 : \color{orangered}{ 41 } }{ 41 : \color{orangered}{ 41 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{1}{1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}1\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{41}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \sqrt{41} } \cdot \sqrt{41} = 41 $$ Simplify denominator. $$ \color{blue}{ \sqrt{41} } \cdot \sqrt{41} = 41 $$ |
| ③ | Divide both the top and bottom numbers by $ \color{orangered}{ 41 } $. |
| ④ | Remove 1 from denominator. |
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