Question
Answer
$$\dfrac{\sqrt{39}}{\sqrt{43}}=\dfrac{\sqrt{1677}}{43}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{39}}{\sqrt{43}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{\sqrt{39}}{\sqrt{43}}\frac{\sqrt{43}}{\sqrt{43}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{\sqrt{1677}}{43}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{43}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \sqrt{39} } \cdot \sqrt{43} = \sqrt{1677} $$ Simplify denominator. $$ \color{blue}{ \sqrt{43} } \cdot \sqrt{43} = 43 $$ |
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