Question
Answer
$$\dfrac{\sqrt{3}\cdot(\sqrt{6}+\sqrt{10})}{1}=3\sqrt{2}+\sqrt{30}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{3}\cdot(\sqrt{6}+\sqrt{10})}{1}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3\sqrt{2}+\sqrt{30}}{1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3\sqrt{2}+\sqrt{30}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{3} } \cdot \left( \sqrt{6} + \sqrt{10}\right) = \color{blue}{ \sqrt{3}} \cdot \sqrt{6}+\color{blue}{ \sqrt{3}} \cdot \sqrt{10} = \\ = 3 \sqrt{2} + \sqrt{30} $$ |
| ② | Remove 1 from denominator. |
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