Question
Answer
$$\dfrac{\sqrt{17}}{\sqrt{18}}=\dfrac{\sqrt{34}}{6}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{17}}{\sqrt{18}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{\sqrt{17}}{\sqrt{18}}\frac{\sqrt{18}}{\sqrt{18}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{3\sqrt{34}}{18} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{\sqrt{34}}{6}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{18}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \sqrt{17} } \cdot \sqrt{18} = 3 \sqrt{34} $$ Simplify denominator. $$ \color{blue}{ \sqrt{18} } \cdot \sqrt{18} = 18 $$ |
| ③ | Divide both numerator and denominator by 3. |
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