Question
Answer
$$\dfrac{\sqrt{16}}{\sqrt{9}}=\dfrac{4}{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{16}}{\sqrt{9}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{\sqrt{16}}{\sqrt{9}}\frac{\sqrt{9}}{\sqrt{9}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{12}{9} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}} \frac{ 12 : \color{orangered}{ 3 } }{ 9 : \color{orangered}{ 3 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{4}{3}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{9}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \sqrt{16} } \cdot \sqrt{9} = 12 $$ Simplify denominator. $$ \color{blue}{ \sqrt{9} } \cdot \sqrt{9} = 9 $$ |
| ③ | Divide both the top and bottom numbers by $ \color{orangered}{ 3 } $. |
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