Question
Answer
$$\dfrac{\sqrt{15}+\sqrt{21}+\sqrt{36}+5}{\sqrt{3}+\sqrt{7}+2\sqrt{5}}=\dfrac{\sqrt{15}+\sqrt{21}+11}{\sqrt{3}+\sqrt{7}+2\sqrt{5}}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{\sqrt{15}+\sqrt{21}+\sqrt{36}+5}{\sqrt{3}+\sqrt{7}+2\sqrt{5}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{\sqrt{15}+\sqrt{21}+6+5}{\sqrt{3}+\sqrt{7}+2\sqrt{5}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{\sqrt{15}+\sqrt{21}+11}{\sqrt{3}+\sqrt{7}+2\sqrt{5}}\end{aligned} $$ | |
| ① | $$ \sqrt{36} = 6 $$ |
| ② | Simplify numerator and denominator |
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