Question
Answer
$$\dfrac{9\sqrt{72}}{72}=\dfrac{3\sqrt{2}}{4}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{9\sqrt{72}}{72}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{54\sqrt{2}}{72} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{ 54 \sqrt{ 2 } : \color{blue}{ 18 } } { 72 : \color{blue}{ 18 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{3\sqrt{2}}{4}\end{aligned} $$ | |
| ① | $$ 9 \sqrt{72} =
9 \sqrt{ 6 ^2 \cdot 2 } =
9 \sqrt{ 6 ^2 } \, \sqrt{ 2 } =
9 \cdot 6 \sqrt{ 2 } =
54 \sqrt{ 2 } $$ |
| ② | Divide numerator and denominator by $ \color{blue}{ 18 } $. |
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