Question
Answer
$$\dfrac{9}{-5+\sqrt{3}}=\dfrac{-45-9\sqrt{3}}{22}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{9}{-5+\sqrt{3}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{9}{-5+\sqrt{3}}\frac{-5-\sqrt{3}}{-5-\sqrt{3}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{-45-9\sqrt{3}}{25+5\sqrt{3}-5\sqrt{3}-3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{-45-9\sqrt{3}}{22}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ -5- \sqrt{3}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ 9 } \cdot \left( -5- \sqrt{3}\right) = \color{blue}{9} \cdot-5+\color{blue}{9} \cdot- \sqrt{3} = \\ = -45- 9 \sqrt{3} $$ Simplify denominator. $$ \color{blue}{ \left( -5 + \sqrt{3}\right) } \cdot \left( -5- \sqrt{3}\right) = \color{blue}{-5} \cdot-5\color{blue}{-5} \cdot- \sqrt{3}+\color{blue}{ \sqrt{3}} \cdot-5+\color{blue}{ \sqrt{3}} \cdot- \sqrt{3} = \\ = 25 + 5 \sqrt{3}- 5 \sqrt{3}-3 $$ |
| ③ | Simplify numerator and denominator |
This page was created using
Rationalize Denominator Calculator