Question
Answer
$$\dfrac{7}{\sqrt{98}}=\dfrac{\sqrt{2}}{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{7}{\sqrt{98}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}} \frac{ 7 }{\sqrt{ 98 }} \times \frac{ \color{orangered}{\sqrt{ 98 }} }{ \color{orangered}{\sqrt{ 98 }}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{7\sqrt{98}}{98} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}} \frac{ 7 \sqrt{ 49 \cdot 2 }}{ 98 } \xlongequal{ } \\[1 em] & \xlongequal{ } \frac{ 7 \cdot 7 \sqrt{ 2 } }{ 98 } \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{49\sqrt{2}}{98} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}} \frac{ 49 \sqrt{ 2 } : \color{blue}{ 49 } }{ 98 : \color{blue}{ 49 } } \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{\sqrt{2}}{2}\end{aligned} $$ | |
| ① | Multiply both top and bottom by $ \color{orangered}{ \sqrt{ 98 }}$. |
| ② | In denominator we have $ \sqrt{ 98 } \cdot \sqrt{ 98 } = 98 $. |
| ③ | Simplify $ \sqrt{ 98 } $. |
| ④ | Divide both the top and bottom numbers by $ \color{blue}{ 49 }$. |
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