Question
Answer
$$\dfrac{7}{\sqrt{54}\cdot0}=\dfrac{\sqrt{6}}{0}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{7}{\sqrt{54}\cdot0}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{7}{\sqrt{54}\cdot0}\frac{\sqrt{54}}{\sqrt{54}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{21\sqrt{6}}{0} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{\sqrt{6}}{0}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{54}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ 7 } \cdot \sqrt{54} = 21 \sqrt{6} $$ Simplify denominator. $$ \color{blue}{ 0 \sqrt{54} } \cdot \sqrt{54} = 0 $$ |
| ③ | Cannot divide by zero. |
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