Question
Answer
$$\dfrac{6+4\sqrt{3}}{6-4\sqrt{3}}=-7-4\sqrt{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{6+4\sqrt{3}}{6-4\sqrt{3}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{6+4\sqrt{3}}{6-4\sqrt{3}}\frac{6+4\sqrt{3}}{6+4\sqrt{3}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{36+24\sqrt{3}+24\sqrt{3}+48}{36+24\sqrt{3}-24\sqrt{3}-48} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{84+48\sqrt{3}}{-12} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{7+4\sqrt{3}}{-1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}-\frac{7+4\sqrt{3}}{1} \xlongequal{ } \\[1 em] & \xlongequal{ }-(7+4\sqrt{3}) \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle6}{\textcircled {6}} } }}}-7-4\sqrt{3}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ 6 + 4 \sqrt{3}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \left( 6 + 4 \sqrt{3}\right) } \cdot \left( 6 + 4 \sqrt{3}\right) = \color{blue}{6} \cdot6+\color{blue}{6} \cdot 4 \sqrt{3}+\color{blue}{ 4 \sqrt{3}} \cdot6+\color{blue}{ 4 \sqrt{3}} \cdot 4 \sqrt{3} = \\ = 36 + 24 \sqrt{3} + 24 \sqrt{3} + 48 $$ Simplify denominator. $$ \color{blue}{ \left( 6- 4 \sqrt{3}\right) } \cdot \left( 6 + 4 \sqrt{3}\right) = \color{blue}{6} \cdot6+\color{blue}{6} \cdot 4 \sqrt{3}\color{blue}{- 4 \sqrt{3}} \cdot6\color{blue}{- 4 \sqrt{3}} \cdot 4 \sqrt{3} = \\ = 36 + 24 \sqrt{3}- 24 \sqrt{3}-48 $$ |
| ③ | Simplify numerator and denominator |
| ④ | Divide both numerator and denominator by 12. |
| ⑤ | Place a negative sign in front of a fraction. |
| ⑥ | Remove the parenthesis by changing the sign of each term within them. |
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