Question
Answer
$$\dfrac{5\cdot1}{5\sqrt{4}\cdot1^{71^{13}}}=\dfrac{5}{10\cdot1^{71^{13}}}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{5\cdot1}{5\sqrt{4}\cdot1^{71^{13}}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{5}{5\cdot2\cdot1^{71^{13}}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{5}{10\cdot1^{71^{13}}}\end{aligned} $$ | |
| ① | $ 5 \cdot 1 = 5 $ |
| ② | The square root of $ 4 $ is $ 2 $. |
| ③ | $ 5 \cdot 1 = 5 $ |
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