Question
Answer
$$\dfrac{3\sqrt{72}}{72}=\dfrac{\sqrt{2}}{4}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{3\sqrt{72}}{72}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{18\sqrt{2}}{72} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{\sqrt{2}}{4}\end{aligned} $$ | |
| ① | $$ 3 \sqrt{72} =
3 \sqrt{ 6 ^2 \cdot 2 } =
3 \sqrt{ 6 ^2 } \, \sqrt{ 2 } =
3 \cdot 6 \sqrt{ 2 } =
18 \sqrt{ 2 } $$ |
| ② | Divide both numerator and denominator by 18. |
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