Question
Answer
$$\dfrac{3\sqrt{3}+\sqrt{18}}{3}=\sqrt{3}+\sqrt{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{3\sqrt{3}+\sqrt{18}}{3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3\sqrt{3}+3\sqrt{2}}{3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{\sqrt{3}+\sqrt{2}}{1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\sqrt{3}+\sqrt{2}\end{aligned} $$ | |
| ① | $$ \sqrt{18} =
\sqrt{ 3 ^2 \cdot 2 } =
\sqrt{ 3 ^2 } \, \sqrt{ 2 } =
3 \sqrt{ 2 }$$ |
| ② | Divide both numerator and denominator by 3. |
| ③ | Remove 1 from denominator. |
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