Question
Answer
$$\dfrac{3+3\sqrt{5}}{2\sqrt{20}}=\dfrac{6\sqrt{5}+30}{40}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{3+3\sqrt{5}}{2\sqrt{20}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3+3\sqrt{5}}{2\sqrt{20}}\frac{\sqrt{20}}{\sqrt{20}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{6\sqrt{5}+30}{40}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{20}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ \left( 3 + 3 \sqrt{5}\right) } \cdot \sqrt{20} = \color{blue}{3} \cdot \sqrt{20}+\color{blue}{ 3 \sqrt{5}} \cdot \sqrt{20} = \\ = 6 \sqrt{5} + 30 $$ Simplify denominator. $$ \color{blue}{ 2 \sqrt{20} } \cdot \sqrt{20} = 40 $$ |
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