Question
Answer
$$\dfrac{2}{-6+\sqrt{2}}=\dfrac{-6-\sqrt{2}}{17}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{2}{-6+\sqrt{2}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2}{-6+\sqrt{2}}\frac{-6-\sqrt{2}}{-6-\sqrt{2}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{-12-2\sqrt{2}}{36+6\sqrt{2}-6\sqrt{2}-2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{-12-2\sqrt{2}}{34} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{-6-\sqrt{2}}{17}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ -6- \sqrt{2}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ 2 } \cdot \left( -6- \sqrt{2}\right) = \color{blue}{2} \cdot-6+\color{blue}{2} \cdot- \sqrt{2} = \\ = -12- 2 \sqrt{2} $$ Simplify denominator. $$ \color{blue}{ \left( -6 + \sqrt{2}\right) } \cdot \left( -6- \sqrt{2}\right) = \color{blue}{-6} \cdot-6\color{blue}{-6} \cdot- \sqrt{2}+\color{blue}{ \sqrt{2}} \cdot-6+\color{blue}{ \sqrt{2}} \cdot- \sqrt{2} = \\ = 36 + 6 \sqrt{2}- 6 \sqrt{2}-2 $$ |
| ③ | Simplify numerator and denominator |
| ④ | Divide both numerator and denominator by 2. |
This page was created using
Rationalize Denominator Calculator