Question
Answer
$$\dfrac{12\sqrt{3}+8\sqrt{2}+9\sqrt{3}-6\sqrt{2}}{19}=\dfrac{21\sqrt{3}+2\sqrt{2}}{19}$$
Explanation
| $$ \begin{aligned}\frac{12\sqrt{3}+8\sqrt{2}+9\sqrt{3}-6\sqrt{2}}{19}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{21\sqrt{3}+2\sqrt{2}}{19}\end{aligned} $$ | |
| ① | Simplify numerator and denominator |
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