Question
Answer
$$\dfrac{12\sqrt{11}+24+12\sqrt{3}-22\sqrt{2}-4\sqrt{2}\cdot2-2\sqrt{66}}{144-88}=\dfrac{6\sqrt{11}+12+6\sqrt{3}-15\sqrt{2}-\sqrt{66}}{28}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{12\sqrt{11}+24+12\sqrt{3}-22\sqrt{2}-4\sqrt{2}\cdot2-2\sqrt{66}}{144-88}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{12\sqrt{11}+24+12\sqrt{3}-30\sqrt{2}-2\sqrt{66}}{56} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{6\sqrt{11}+12+6\sqrt{3}-15\sqrt{2}-\sqrt{66}}{28}\end{aligned} $$ | |
| ① | Simplify numerator and denominator |
| ② | Divide both numerator and denominator by 2. |
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