Question
Answer
$$\dfrac{10}{(-1)^{0.5}((-1)^{0.5}+1)((-1)^{0.5}+2)}=\dfrac{5}{3}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{10}{(-1)^{0.5}((-1)^{0.5}+1)((-1)^{0.5}+2)}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{10}{(-1)^{0.5}\cdot(1+1)\cdot(1+2)} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{10}{(-1)^{0.5}\cdot2\cdot3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}\frac{10}{1\cdot2\cdot3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}\frac{10}{2\cdot3} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle5}{\textcircled {5}} } }}}\frac{10}{6} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle6}{\textcircled {6}} } }}} \frac{ 10 : \color{orangered}{ 2 } }{ 6 : \color{orangered}{ 2 }} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{5}{3}\end{aligned} $$ | |
| ① | A non-zero polynomial raised to the power of 0 equals 1. |
| ② | A non-zero polynomial raised to the power of 0 equals 1. |
| ③ | A non-zero polynomial raised to the power of 0 equals 1. |
| ④ | $ 1 \cdot 2 = 2 $ |
| ⑤ | $ 2 \cdot 3 = 6 $ |
| ⑥ | Divide both the top and bottom numbers by $ \color{orangered}{ 2 } $. |
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