Question
Answer
$$\dfrac{1}{\sqrt{6}\cdot\sqrt{7}}=\dfrac{\sqrt{42}}{42}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{1}{\sqrt{6}\cdot\sqrt{7}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{1}{\sqrt{6}\cdot\sqrt{7}}\frac{\sqrt{42}}{\sqrt{42}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}\frac{\sqrt{42}}{42}\end{aligned} $$ | |
| ① | Multiply the numerator and denominator by the conjugate of the denominator . $$\color{blue}{ \sqrt{42}} $$. |
| ② | Multiply in a numerator. $$ \color{blue}{ 1 } \cdot \sqrt{42} = \sqrt{42} $$ Simplify denominator. $$ \color{blue}{ \sqrt{42} } \cdot \sqrt{42} = 42 $$ |
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