Question
Answer
$$\dfrac{1}{7-\sqrt{3}^2}=\dfrac{1}{4}$$
Explanation
| $$ \begin{aligned}\frac{1}{7-\sqrt{3}^2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{1}{7-3} \xlongequal{ } \\[1 em] & \xlongequal{ }\frac{1}{4}\end{aligned} $$ | |
| ① | $$ \sqrt{3}^2 =
\sqrt{3} ^2 =
\lvert 3 \rvert =
3 $$ |
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