Question
Answer
$$\dfrac{(2\sqrt{3}-3\sqrt{6})^2}{1}=66-36\sqrt{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\frac{(2\sqrt{3}-3\sqrt{6})^2}{1}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{12-18\sqrt{2}-18\sqrt{2}+54}{1} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}66-36\sqrt{2}\end{aligned} $$ | |
| ① | $$ (2\sqrt{3}-3\sqrt{6})^2 = \left( 2 \sqrt{3}- 3 \sqrt{6} \right) \cdot \left( 2 \sqrt{3}- 3 \sqrt{6} \right) = 12- 18 \sqrt{2}- 18 \sqrt{2} + 54 $$ |
| ② | Remove 1 from denominator. |
This page was created using
Rationalize Denominator Calculator