Question
Find the prime factorization of number 9999900000.
Answer
The prime factorization of 9999900000 is:
$$ 9999900000 = 2\cdot2\cdot2\cdot2\cdot2\cdot3\cdot3\cdot5\cdot5\cdot5\cdot5\cdot5\cdot41\cdot271 $$Which is the same as :
$$ 9999900000 = 2^{5}\cdot3^{2}\cdot5^{5}\cdot41\cdot271 $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 9999900000 can be written as 10 × 999990000. |
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| 10 can be written as 2 × 5. |
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| 999990000 can be written as 10 × 99999000. |
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| 10 can be written as 2 × 5. |
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| 99999000 can be written as 10 × 9999900. |
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| 10 can be written as 2 × 5. |
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| 9999900 can be written as 10 × 999990. |
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| 10 can be written as 2 × 5. |
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| 999990 can be written as 10 × 99999. |
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| 10 can be written as 2 × 5. |
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| 99999 can be written as 3 × 33333. |
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| 33333 can be written as 3 × 11111. |
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| 11111 can be written as 41 × 271. |
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| The end nodes are the prime factors of the number 9999900000. |
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