Question
Find the prime factorization of number 74800.
Answer
The prime factorization of 74800 is:
$$ 74800 = 2\cdot2\cdot2\cdot2\cdot5\cdot5\cdot11\cdot17 $$Which is the same as :
$$ 74800 = 2^{4}\cdot5^{2}\cdot11\cdot17 $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 74800 can be written as 10 × 7480. |
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| 10 can be written as 2 × 5. |
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| 7480 can be written as 10 × 748. |
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| 10 can be written as 2 × 5. |
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| 748 can be written as 2 × 374. |
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| 374 can be written as 2 × 187. |
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| 187 can be written as 11 × 17. |
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| The end nodes are the prime factors of the number 74800. |
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