Question
Find the prime factorization of number 7412.
Answer
The prime factorization of 7412 is:
$$ 7412 = 2\cdot2\cdot17\cdot109 $$Which is the same as :
$$ 7412 = 2^{2}\cdot17\cdot109 $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 7412 can be written as 2 × 3706. |
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| 3706 can be written as 2 × 1853. |
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| 1853 can be written as 17 × 109. |
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| The end nodes are the prime factors of the number 7412. |
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