Question
Find the prime factorization of number 43308.
Answer
The prime factorization of 43308 is:
$$ 43308 = 2\cdot2\cdot3\cdot3\cdot3\cdot401 $$Which is the same as :
$$ 43308 = 2^{2}\cdot3^{3}\cdot401 $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 43308 can be written as 2 × 21654. |
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| 21654 can be written as 2 × 10827. |
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| 10827 can be written as 3 × 3609. |
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| 3609 can be written as 3 × 1203. |
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| 1203 can be written as 3 × 401. |
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| The end nodes are the prime factors of the number 43308. |
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