Question
Find the prime factorization of number 3430000.
Answer
The prime factorization of 3430000 is:
$$ 3430000 = 2\cdot2\cdot2\cdot2\cdot5\cdot5\cdot5\cdot5\cdot7\cdot7\cdot7 $$Which is the same as :
$$ 3430000 = 2^{4}\cdot5^{4}\cdot7^{3} $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 3430000 can be written as 10 × 343000. |
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| 10 can be written as 2 × 5. |
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| 343000 can be written as 10 × 34300. |
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| 10 can be written as 2 × 5. |
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| 34300 can be written as 10 × 3430. |
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| 10 can be written as 2 × 5. |
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| 3430 can be written as 10 × 343. |
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| 10 can be written as 2 × 5. |
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| 343 can be written as 7 × 49. |
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| 49 can be written as 7 × 7. |
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| The end nodes are the prime factors of the number 3430000. |
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