Question
Find the prime factorization of number 24012.
Answer
The prime factorization of 24012 is:
$$ 24012 = 2\cdot2\cdot3\cdot3\cdot23\cdot29 $$Which is the same as :
$$ 24012 = 2^{2}\cdot3^{2}\cdot23\cdot29 $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 24012 can be written as 2 × 12006. |
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| 12006 can be written as 2 × 6003. |
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| 6003 can be written as 3 × 2001. |
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| 2001 can be written as 3 × 667. |
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| 667 can be written as 23 × 29. |
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| The end nodes are the prime factors of the number 24012. |
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