Question
Find the prime factorization of number 230712543.
Answer
The prime factorization of 230712543 is:
$$ 230712543 = 3\cdot3\cdot3\cdot3\cdot401\cdot7103 $$Which is the same as :
$$ 230712543 = 3^{4}\cdot401\cdot7103 $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 230712543 can be written as 3 × 76904181. |
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| 76904181 can be written as 3 × 25634727. |
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| 25634727 can be written as 3 × 8544909. |
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| 8544909 can be written as 3 × 2848303. |
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| 2848303 can be written as 401 × 7103. |
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| The end nodes are the prime factors of the number 230712543. |
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