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Question

Find the prime factorization of number 1848.

Answer

The prime factorization of 1848 is:

$$ 1848 = 2\cdot2\cdot2\cdot3\cdot7\cdot11 $$

Which is the same as :

$$ 1848 = 2^{3}\cdot3\cdot7\cdot11 $$

Explanation

Prime factorization can be nicely visualized by creating a factorization tree.

1848 can be written as 2 × 924.
  • 1848
    • 2
    • 924
924 can be written as 2 × 462.
  • 1848
    • 2
    • 924
      • 462
      • 2
462 can be written as 2 × 231.
  • 1848
    • 2
    • 924
      • 462
        • 2
        • 231
      • 2
231 can be written as 3 × 77.
  • 1848
    • 2
    • 924
      • 462
        • 2
        • 231
          • 77
          • 3
      • 2
77 can be written as 7 × 11.
  • 1848
    • 2
    • 924
      • 462
        • 2
        • 231
          • 77
            • 7
            • 11
          • 3
      • 2
The end nodes are the prime factors of the number 1848.
  • 1848
    • 2
    • 924
      • 462
        • 2
        • 231
          • 77
            • 7
            • 11
          • 3
      • 2
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Prime factorization calculator