Question
Find the prime factorization of number 1812.
Answer
The prime factorization of 1812 is:
$$ 1812 = 2\cdot2\cdot3\cdot151 $$Which is the same as :
$$ 1812 = 2^{2}\cdot3\cdot151 $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 1812 can be written as 2 × 906. |
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| 906 can be written as 2 × 453. |
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| 453 can be written as 3 × 151. |
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| The end nodes are the prime factors of the number 1812. |
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