Question
Find the prime factorization of number 1808.
Answer
The prime factorization of 1808 is:
$$ 1808 = 2\cdot2\cdot2\cdot2\cdot113 $$Which is the same as :
$$ 1808 = 2^{4}\cdot113 $$Explanation
Prime factorization can be nicely visualized by creating a factorization tree.
| 1808 can be written as 2 × 904. |
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| 904 can be written as 2 × 452. |
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| 452 can be written as 2 × 226. |
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| 226 can be written as 2 × 113. |
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| The end nodes are the prime factors of the number 1808. |
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