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Question

Find the prime factorization of number 1200.

Answer

The prime factorization of 1200 is:

$$ 1200 = 2\cdot2\cdot2\cdot2\cdot3\cdot5\cdot5 $$

Which is the same as :

$$ 1200 = 2^{4}\cdot3\cdot5^{2} $$

Explanation

Prime factorization can be nicely visualized by creating a factorization tree.

1200 can be written as 10 × 120.
  • 1200
    • 10
    • 120
10 can be written as 2 × 5.
  • 1200
    • 10
      • 5
      • 2
    • 120
120 can be written as 10 × 12.
  • 1200
    • 10
      • 5
      • 2
    • 120
      • 10
      • 12
10 can be written as 2 × 5.
  • 1200
    • 10
      • 5
      • 2
    • 120
      • 10
        • 5
        • 2
      • 12
12 can be written as 2 × 6.
  • 1200
    • 10
      • 5
      • 2
    • 120
      • 10
        • 5
        • 2
      • 12
        • 2
        • 6
6 can be written as 2 × 3.
  • 1200
    • 10
      • 5
      • 2
    • 120
      • 10
        • 5
        • 2
      • 12
        • 2
        • 6
          • 3
          • 2
The end nodes are the prime factors of the number 1200.
  • 1200
    • 10
      • 5
      • 2
    • 120
      • 10
        • 5
        • 2
      • 12
        • 2
        • 6
          • 3
          • 2
This page was created using
Prime factorization calculator