Question
Find the polynomial having roots at $ 12 $ , $ 29 $ and $ 2006 $ .
Answer
The polynomial generated from the given zeros is: $ P(x) = x^3-2047x^2+82594x-698088 $
Explanation
Step 1: Turn the zeros into factors:
| Zero | Factor |
| $ 12 $ | $ x-12 $ |
| $ 29 $ | $ x-29 $ |
| $ 2006 $ | $ x-2006 $ |
Step 2: Multiply the factors together:
$$ P(x) = \left( x-12 \right) \cdot \left( x-29 \right) \cdot \left( x-2006 \right) = x^3-2047x^2+82594x-698088 $$This page was created using
Polynomial From Roots Calculator