Question
Find the polynomial having roots at $ \dfrac{ 11 }{ 10 } $ , $ \dfrac{ 3 }{ 2 } $ , $ 2 $ and $ \dfrac{ 21 }{ 10 } $ .
Answer
The polynomial generated from the given zeros is: $ P(x) = 200x^4-1340x^3+3302x^2-3537x+1386 $
Explanation
Step 1: Turn the zeros into factors:
| Zero | Factor |
| $ \dfrac{ 11 }{ 10 } $ | $ 10x-11 $ |
| $ \dfrac{ 3 }{ 2 } $ | $ 2x-3 $ |
| $ 2 $ | $ x-2 $ |
| $ \dfrac{ 21 }{ 10 } $ | $ 10x-21 $ |
Step 2: Multiply the factors together:
$$ P(x) = \left( 10x-11 \right) \cdot \left( 2x-3 \right) \cdot \left( x-2 \right) \cdot \left( 10x-21 \right) = 200x^4-1340x^3+3302x^2-3537x+1386 $$This page was created using
Polynomial From Roots Calculator