Question
Find the polynomial having roots at $ \dfrac{ 83 }{ 100 } $ and $ 9 $ .
Answer
The polynomial generated from the given zeros is: $ P(x) = 100x^2-983x+747 $
Explanation
Step 1: Turn the zeros into factors:
| Zero | Factor |
| $ \dfrac{ 83 }{ 100 } $ | $ 100x-83 $ |
| $ 9 $ | $ x-9 $ |
Step 2: Multiply the factors together:
$$ P(x) = \left( 100x-83 \right) \cdot \left( x-9 \right) = 100x^2-983x+747 $$This page was created using
Polynomial From Roots Calculator