Question
Factor polynomial $$ z^{6}+512 $$
Answer
$$ z^{6}+512 = ( z^{2}+8 )( z^{4}-8z^{2}+64 ) $$
Explanation
To factor $ z^{6}+512 $ we can use sum of cubes formula:
$$ I^3 - II^3 = (I + II)(I^2 - I \cdot II + II^2) $$After putting $ I = z^{2} $ and $ II = 8 $ , we have:
$$ z^{6}+512 = ( z^{2}+8 ) ( z^{4}-8z^{2}+64 ) $$This page was created using
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