Question
Factor polynomial $$ z^{3}-64s^{3} $$
Answer
$$ z^{3}-64s^{3} = (z-4s)(z^{2}+4sz+16s^{2}) $$
Explanation
To factor $ z^{3}-64s^{3} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = z $ and $ II = 4s $ , we have:
$$ z^{3}-64s^{3} = ( z-4s ) ( z^{2}+4sz+16s^{2} ) $$This page was created using
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