Question
Factor polynomial $$ x^{3}-x^{2}+9x-9 $$
Answer
$$ x^{3}-x^{2}+9x-9 = ( x^{2}+9 )( x-1 ) $$
Explanation
To factor $ x^{3}-x^{2}+9x-9 $ we can use factoring by grouping:
Group $ \color{blue}{ x^{3} }$ with $ \color{blue}{ -x^{2} }$ and $ \color{red}{ 9x }$ with $ \color{red}{ -9 }$ then factor each group.
$$ \begin{aligned} x^{3}-x^{2}+9x-9 = ( \color{blue}{ x^{3}-x^{2} } ) + ( \color{red}{ 9x-9 }) &= \\ &= \color{blue}{ x^{2}( x-1 )} + \color{red}{ 9( x-1 ) } = \\ &= (x^{2}+9)(x-1) \end{aligned} $$This page was created using
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