Question
Factor polynomial $$ x^{3}-8y^{6} $$
Answer
$$ x^{3}-8y^{6} = (x-2y^{2})(x^{2}+2xy^{2}+4y^{4}) $$
Explanation
To factor $ x^{3}-8y^{6} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = x $ and $ II = 2y^2 $ , we have:
$$ x^{3}-8y^{6} = ( x-2y^{2} ) ( x^{2}+2xy^{2}+4y^{4} ) $$This page was created using
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