Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = 1 } ~ \text{ and } ~ \color{red}{ c = -132 }$$Now we must discover two numbers that sum up to $ \color{blue}{ 1 } $ and multiply to $ \color{red}{ -132 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = -132 }$.
| PRODUCT = -132 | |
| -1 132 | 1 -132 |
| -2 66 | 2 -66 |
| -3 44 | 3 -44 |
| -4 33 | 4 -33 |
| -6 22 | 6 -22 |
| -11 12 | 11 -12 |
Step 3: Find out which pair sums up to $\color{blue}{ b = 1 }$
| PRODUCT = -132 and SUM = 1 | |
| -1 132 | 1 -132 |
| -2 66 | 2 -66 |
| -3 44 | 3 -44 |
| -4 33 | 4 -33 |
| -6 22 | 6 -22 |
| -11 12 | 11 -12 |
Step 4: Put -11 and 12 into placeholders to get factored form.
$$ \begin{aligned} x^{2}+x-132 & = (x + \color{orangered}{\square} )(x + \color{orangered}{\square}) \\ x^{2}+x-132 & = (x -11)(x + 12) \end{aligned} $$