Question
Factor polynomial $$ x^{2}+8x-220 $$
Answer
It seems that $ x^{2}+8x-220 $ cannot be factored out.
Explanation
Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = 8 } ~ \text{ and } ~ \color{red}{ c = -220 }$$Now we must discover two numbers that sum up to $ \color{blue}{ 8 } $ and multiply to $ \color{red}{ -220 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = -220 }$.
| PRODUCT = -220 | |
| -1 220 | 1 -220 |
| -2 110 | 2 -110 |
| -4 55 | 4 -55 |
| -5 44 | 5 -44 |
| -10 22 | 10 -22 |
| -11 20 | 11 -20 |
Step 3: Because none of these pairs will give us a sum of $ \color{blue}{ 8 }$, we conclude the polynomial cannot be factored.
This page was created using
Polynomial Factoring Calculator