It seems that $ x^{2}+5x-100 $ cannot be factored out.
Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = 5 } ~ \text{ and } ~ \color{red}{ c = -100 }$$Now we must discover two numbers that sum up to $ \color{blue}{ 5 } $ and multiply to $ \color{red}{ -100 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = -100 }$.
| PRODUCT = -100 | |
| -1 100 | 1 -100 |
| -2 50 | 2 -50 |
| -4 25 | 4 -25 |
| -5 20 | 5 -20 |
| -10 10 | 10 -10 |
Step 3: Because none of these pairs will give us a sum of $ \color{blue}{ 5 }$, we conclude the polynomial cannot be factored.