Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = 26 } ~ \text{ and } ~ \color{red}{ c = 168 }$$Now we must discover two numbers that sum up to $ \color{blue}{ 26 } $ and multiply to $ \color{red}{ 168 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = 168 }$.
| PRODUCT = 168 | |
| 1 168 | -1 -168 |
| 2 84 | -2 -84 |
| 3 56 | -3 -56 |
| 4 42 | -4 -42 |
| 6 28 | -6 -28 |
| 7 24 | -7 -24 |
| 8 21 | -8 -21 |
| 12 14 | -12 -14 |
Step 3: Find out which pair sums up to $\color{blue}{ b = 26 }$
| PRODUCT = 168 and SUM = 26 | |
| 1 168 | -1 -168 |
| 2 84 | -2 -84 |
| 3 56 | -3 -56 |
| 4 42 | -4 -42 |
| 6 28 | -6 -28 |
| 7 24 | -7 -24 |
| 8 21 | -8 -21 |
| 12 14 | -12 -14 |
Step 4: Put 12 and 14 into placeholders to get factored form.
$$ \begin{aligned} x^{2}+26x+168 & = (x + \color{orangered}{\square} )(x + \color{orangered}{\square}) \\ x^{2}+26x+168 & = (x + 12)(x + 14) \end{aligned} $$