Question
Factor polynomial $$ x^{2}+20xy+100y^{2} $$
Answer
$$ x^{2}+20xy+100y^{2} = (x+10y)(x+10y) $$
Explanation
Note that the polynomial $ x^2+20xy+100y^2 $ is a perfect square trinomial, so we will use the following formula.
$$ A^2 + 2AB + B^2 = (A + B)^2 $$In this example we have $ \color{blue}{ A = x } $ and $ \color{red}{ B = 10y } $ so,
$$ x^2+20xy+100y^2 = ( \color{blue}{ x } + \color{red}{ 10y } )^2 $$This page was created using
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