It seems that $ 16x^{2}+67x+53 $ cannot be factored out.
Step 1: Identify constants $ a $ , $ b $ and $ c $.
$ a $ is a number in front of the $ x^2 $ term $ b $ is a number in front of the $ x $ term and $ c $ is a constant. In this case:
Step 2: Multiply the leading coefficient $\color{blue}{ a = 16 }$ by the constant term $\color{blue}{c = 53} $.
$$ a \cdot c = 848 $$Step 3: Find out two numbers that multiply to $ a \cdot c = 848 $ and add to $ b = 67 $.
Step 4: All pairs of numbers with a product of $ 848 $ are:
| PRODUCT = 848 | |
| 1 848 | -1 -848 |
| 2 424 | -2 -424 |
| 4 212 | -4 -212 |
| 8 106 | -8 -106 |
| 16 53 | -16 -53 |
Step 5: Find out which factor pair sums up to $\color{blue}{ b = 67 }$
Step 6: Because none of these pairs will give us a sum of $ \color{blue}{ 67 }$, we conclude the polynomial cannot be factored.