Question
Factor polynomial $$ x^{12}+8 $$
Answer
$$ x^{12}+8 = ( x^{4}+2 )( x^{8}-2x^{4}+4 ) $$
Explanation
To factor $ x^{12}+8 $ we can use sum of cubes formula:
$$ I^3 - II^3 = (I + II)(I^2 - I \cdot II + II^2) $$After putting $ I = x^{4} $ and $ II = 2 $ , we have:
$$ x^{12}+8 = ( x^{4}+2 ) ( x^{8}-2x^{4}+4 ) $$This page was created using
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