Question
Factor polynomial $$ r^{3}s^{3}-t^{12} $$
Answer
$$ r^{3}s^{3}-t^{12} = (rs-t^{4})(r^{2}s^{2}+rst^{4}+t^{8}) $$
Explanation
To factor $ r^{3}s^{3}-t^{12} $ we can use difference of cubes formula:
$$ I^3 - II^3 = (I - II) (I^2 + I \cdot II + II^2) $$After putting $ I = rs $ and $ II = t^4 $ , we have:
$$ r^{3}s^{3}-t^{12} = ( rs-t^{4} ) ( r^{2}s^{2}+rst^{4}+t^{8} ) $$This page was created using
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