Step 1: Identify constants $ \color{blue}{ b }$ and $\color{red}{ c }$. ( $ \color{blue}{ b }$ is a number in front of the $ x $ term and $ \color{red}{ c } $ is a constant). In our case:
$$ \color{blue}{ b = 14 } ~ \text{ and } ~ \color{red}{ c = 48 }$$Now we must discover two numbers that sum up to $ \color{blue}{ 14 } $ and multiply to $ \color{red}{ 48 } $.
Step 2: Find out pairs of numbers with a product of $\color{red}{ c = 48 }$.
| PRODUCT = 48 | |
| 1 48 | -1 -48 |
| 2 24 | -2 -24 |
| 3 16 | -3 -16 |
| 4 12 | -4 -12 |
| 6 8 | -6 -8 |
Step 3: Find out which pair sums up to $\color{blue}{ b = 14 }$
| PRODUCT = 48 and SUM = 14 | |
| 1 48 | -1 -48 |
| 2 24 | -2 -24 |
| 3 16 | -3 -16 |
| 4 12 | -4 -12 |
| 6 8 | -6 -8 |
Step 4: Put 6 and 8 into placeholders to get factored form.
$$ \begin{aligned} n^{2}+14n+48 & = (x + \color{orangered}{\square} )(x + \color{orangered}{\square}) \\ n^{2}+14n+48 & = (x + 6)(x + 8) \end{aligned} $$