Question
Factor polynomial $$ n^{2}-64 $$
Answer
$$ n^{2}-64 = ( n-8 )( n+8 ) $$
Explanation
Rewrite $ n^{2}-64 $ as:
$$ n^{2}-64 = (n)^2 - (8)^2 $$Now we can apply the difference of squares formula.
$$ I^2 - II^2 = (I - II)(I + II) $$After putting $ I = n $ and $ II = 8 $ , we have:
$$ n^{2}-64 = (n)^2 - (8)^2 = ( n-8 ) ( n+8 ) $$This page was created using
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